30 Aug
2009
30 Aug
'09
9:16 p.m.
Hi
oh so my logic was wrong. I would have thought that the above would not show in case both mtb AND bicycle route is set, and not OR. So how would I do that, a rule that needs all three to be true like this: ( tunnel=yes & route!=mtb & route!= bicycle ) [....] ?
Yes, that would be true for tunnel=yes and route=abc, but not when route=mtb or route=bicycle, if that is what you wanted to do. The parentheses are not needed. tunnel = yes & route!=mtb & route!=bicycle is the same as: tunnel = yes & !(route = mtb | route = bicycle) which might be a clearer way to write it. This is supposed to be supported but was never completely implemented. I have a fix for that which I will commit in the next few minutes. ..Steve