Hi

  

oh so my logic was wrong. I would have thought that the above would not
show in case both mtb AND bicycle route is set, and not OR.
So how would I do that, a rule that needs all three to be true like
this: ( tunnel=yes & route!=mtb & route!= bicycle ) [....] ?
    

Yes, that would be true for tunnel=yes and route=abc, but not when
route=mtb or route=bicycle, if that is what you wanted to do.
The parentheses are not needed.

   tunnel = yes & route!=mtb & route!=bicycle

is the same as:

   tunnel = yes & !(route = mtb | route = bicycle)
  

which might be a clearer way to write it.  This is supposed to
be supported but was never completely implemented. I have
a fix for that which I will commit in the next few minutes.

..Steve
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