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11 Aug
2009
11 Aug
'09
7:05 p.m.
Chris Miller schreef:
but my impression is that the conclusion was that the splitter should be rounding areas off to boundaries in multiples of 4096 rather than 2048?
As far as I've seen - thanks to Steve Ratcliffe's findings - divisible by 2048 is enough, if you make sure that the difference is a multiple of 4096. (i.e. if your bounds are 0x123800 and 0x456800, that is OK; but 0x123800 and 0x456000 is not OK). Anyway, dividing by 4096 is a good method of achieving this. V.